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∆Abc is an Equilateral Triangle. Point P is on Base Bc Such that Pc = 1 3 Bc, If Ab = 6 Cm Find Ap. - Geometry | Shaalaa.com
The base BC of an equilateral triangle ABC lies on y - axis . The coordinates of the point C are (0, - 3). If the origin is the mid - point
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OBMEP - O triângulo ABC é isósceles de Base BC e o ângulo BÂC mede 30°. O triângulo BDC é isósceles. - YouTube
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In the given figure, ABC and DBC are two triangles on the same base BC. If AD intersects BC at O, show that Ar(ABC)Ar (DBC) = AODO
Question 3 - ABC and DBC are two triangles on same base BC
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